The following is a very important application of actions on -subsets: The regular representation of yields, in accordance with , the -sets , for . If is finite and a prime dividing , say , where does not divide , then we can put and consider the particular -set , as H. Wielandt did in his famous proof of Sylow's Theorem in order to show that possesses subgroups of order . His argument runs as follows: is the exact power of dividing the order of . This is clear from
as each power of contained in the denominator cancels. Thus -subsets exist, the orbit length of which is not divisible by . We consider such an and show that its stabilizer is of order by proving that is both an upper and lower bound: For each and we have that , hence
On the other hand, the fact that does not divide the orbit length yields
This proves the first item of
. Sylow's Theorem
Assume to be a finite group
and to be a prime divisor of its order. Then
The subgroups of the maximal -power order are called
the Sylow -subgroups
of They have the following properties:
The proof of the second and third item follows from a consideration of double cosets. Assume a -subgroup of and a Sylow -subgroup Then we derive from that
where denotes a transversal of If all the intersections in the denominator on the right hand side were proper subgroups of then the right hand side were divisible by which contradicts the left hand side. Hence there must exist a such that Since is a Sylow -subgroup, too, is contained in a Sylow subgroup, which proves the second item.
The third item follows by taking for a Sylow -subgroup
shows that for a suitable where denotes a transversal of
This example shows clearly that the consideration of suitable group actions can be very helpful, at least in group theory. Applications to other fields of mathematics will follow soon.
Exercises
E . Prove that the number of Sylow -subgroups divides the order of and is congruent 1 modulo for each prime divisor of the order of